6r^2+6r*12=0

Solution for 6r^2+6r*12=0 equation:

6r^2+6r*12=0

Wy multiply elements

6r^2+72r=0

a = 6; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·6·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*6}=\frac{-144}{12}
=-12
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*6}=\frac{0}{12}
=0
$